Відео

Thanks

Thank you for the great work

Thank you for the great work

sir how you get cct = 0.714ns (how to calculate it ?) 37:03

goat

sir i think it will exp(a) in 26:25 or it should be ln(gamma)

Rata system

sir can you upload video explaining the graph in animation

at 29:10 how it is 1/2 * D(E_f) * E_g, is half coming because of probability near fermi surface is 1/2 and interval is E_g+- 1/2 but he's telling something else about 2 pairs of electrons at 42:43 right top most diagram is for Super conductor not ideal conductor, bottom one is ideal conductor (just label position ambiguity if anyone is confused)

You are that an excellent lectureer❤

Zabardast. Very nice

Good lecture 😊

Lots of times "agrees" was said when in fact the professor meant "disagrees".

please create in hindi

A tower, 0.6 m diameter, packed with 50-mm ceramic Raschig rings to a depth of 1.2 m, is to be used for producing a solution of oxygen in water for certain pollution-control operations. The packed space will be pressurized at 5 std atm abs with pure oxygen gas from a gas cylinder. There is to be no gas outlet, and gas will enter from the cylinder only to maintain pressure as oxygen is dissolved. Water will flow down the packing continuously at 1.5 kg/s. The temperature is to be 25°C. Assuming that the entering water is oxygen-free, wiut concentration of oxygen can be expected in the water effluent? data: at 25°C, the diffusivity of oxygen in water - 2.5 * 10 ^ 5 * c * m ^ 2 / s viscosity of water -0.894 cP, and the solubility of oxygen in water follows Henry's law: overline p = 4.38 * 10 ^ 4 * x . where pequilibrium partial pressure, atm, and x mole fruction of oxygen in the liquid. Neglect water vapor content of the gas. Sir could you give the solution for this question it would be very helpful.

it is such a nice video without any distractions and other extra activities

Thanks for sharing video

21:08

did an entire course on SPCMT and didn't understand 70% of it, however, this lecture has really been quite straightforward and creates much needed intuition

Thank you!

Dimensionality is not satisfied in the velocity expression of the Beeman algorithm.

Sir please explain iso 5817 detailed

This is honestly the best video

Thank you sir you saved my tomorrow's exam😀

16:26

35:40

Kuch samaj nhi aaya 😿😢

Anyone give me notes of this lecture please 🥺🙏.

Thanks for the efforts , but could have made nice animations to make complex concepts simpler, rather than boring writings

Thank you ma'am for the wonderful lecture. Could you please let me know, this app is free or not? Thank you

He is teching to himself it seems.

Plzzz class in hindi

Sir your explaining style is not good.

AoA maam thank you so much mari paper thi

nice